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重新排列数组

仲灏2022-11-09约 1 分钟

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重新排列数组

CategoryDifficultyLikesDislikes
algorithmsEasy (85.25%)150-

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给你一个数组 nums ,数组中有 2n 个元素,按 [x1,x2,...,xn,y1,y2,...,yn] 的格式排列。

请你将数组按 [x1,y1,x2,y2,...,xn,yn] 格式重新排列,返回重排后的数组。

示例 1:

输入:nums = [2,5,1,3,4,7], n = 3
输出:[2,3,5,4,1,7] 
解释:由于 x1=2, x2=5, x3=1, y1=3, y2=4, y3=7 ,所以答案为 [2,3,5,4,1,7]

示例 2:

输入:nums = [1,2,3,4,4,3,2,1], n = 4
输出:[1,4,2,3,3,2,4,1]

示例 3:

输入:nums = [1,1,2,2], n = 2
输出:[1,2,1,2]

提示:

  • 1 <= n <= 500
  • nums.length == 2n
  • 1 <= nums[i] <= 10^3

Discussion | Solution


tsx
/*
 * @Author: 仲灏<izhaong@outlook.com>🌶🌶🌶
 * @Date: 2022-11-09 11:11:35
 * @LastEditTime: 2022-11-09 11:40:34
 * @LastEditors: 仲灏<izhaong@outlook.com>🌶🌶🌶
 * @Description:
 * @FilePath: /leetcode/1470.重新排列数组.ts
 */
/*
 * @lc app=leetcode.cn id=1470 lang=typescript
 *
 * [1470] 重新排列数组
 *
 * https://leetcode.cn/problems/shuffle-the-array/description/
 *
 * algorithms
 * Easy (85.25%)
 * Likes:    150
 * Dislikes: 0
 * Total Accepted:    95.8K
 * Total Submissions: 112.4K
 * Testcase Example:  '[2,5,1,3,4,7]\n3'
 *
 * 给你一个数组 nums ,数组中有 2n 个元素,按 [x1,x2,...,xn,y1,y2,...,yn] 的格式排列。
 *
 * 请你将数组按 [x1,y1,x2,y2,...,xn,yn] 格式重新排列,返回重排后的数组。
 *
 *
 *
 * 示例 1:
 *
 * 输入:nums = [2,5,1,3,4,7], n = 3
 * 输出:[2,3,5,4,1,7]
 * 解释:由于 x1=2, x2=5, x3=1, y1=3, y2=4, y3=7 ,所以答案为 [2,3,5,4,1,7]
 *
 *
 * 示例 2:
 *
 * 输入:nums = [1,2,3,4,4,3,2,1], n = 4
 * 输出:[1,4,2,3,3,2,4,1]
 *
 *
 * 示例 3:
 *
 * 输入:nums = [1,1,2,2], n = 2
 * 输出:[1,2,1,2]
 *
 *
 *
 *
 * 提示:
 *
 *
 * 1 <= n <= 500
 * nums.length == 2n
 * 1 <= nums[i] <= 10^3
 *
 *
 */

// @lc code=start
function shuffle(nums: number[], n: number): number[] {
  const res: number[] = new Array(2 * n).fill(0);
  for (let i = 0; i < n; i++) {
    res[2 * i] = nums[i];
    res[2 * i + 1] = nums[i + n];
  }
  return res;
}
// @lc code=end